On passing ${\mathrm{H}}_2\mathrm{S}$ through acidified $\mathrm{K}\mathrm{M}\mathrm{n}{\mathrm{O}}_4$ , we get

• Correct answer
  A

  $\text{S}$
• B

  $\mathrm{M}\mathrm{n}{\mathrm{O}}_2$
• C

  $\mathrm{K}\mathrm{H}\mathrm{S}{\mathrm{O}}_3$
• D

  ${\mathrm{K}}_2\mathrm{S}{\mathrm{O}}_3$

Hence, the correct answer is option: 'A'.