Q163 / 225 · JEE Main 2002 · Physics

On moving a charge of 20 coulombs by $2 \mathrm{~cm}, 2 \mathrm{~J}$ of work is done, then the potential difference between the points is

  • Correct answer
    A
    0.1 V
  • B
    8 V
  • C
    2 V
  • D
    0.5 V

Solution

$$ \mathrm{W}=\mathrm{qV} \Rightarrow \mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=2 / 20=0.1 \mathrm{~V} $$ Here $W$ is the work done in moving charge $q$ from point $A$ to $B$

Hence, the correct answer is option: 'A'.

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