Q14 / 160 · AP EAMCET 2009 · Chemistry

$\mathrm{SiCl}_4$ on hydrolysis forms ' $X$ ' and $\mathrm{HCl}$. Compound ' $X$ ' loses water at $1000^{\circ} \mathrm{C}$ and gives ' $Y$ '. Compounds ' $X$ ' and ' $Y$ ' respectively are

  • A
    $\mathrm{H}_2 \mathrm{SiCl}_6, \mathrm{SiO}_2$
  • B
    $\mathrm{H}_4 \mathrm{SiO}_4, \mathrm{Si}$
  • C
    $\mathrm{SiO}_2, \mathrm{Si}$
  • Correct answer
    D
    $\mathrm{H}_4 \mathrm{SiO}_4, \mathrm{SiO}_2$

Solution

$\begin{array}{r}\mathrm{SiCl}_4+4 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{H}_4 \mathrm{SiO}_4+4 \mathrm{HCl} \\ \mathrm{H}_4 \mathrm{SiO}_4 \frac{\Delta}{1000^{\circ} \mathrm{C}} \mathrm{SiO}_2+2 \mathrm{H}_2 \mathrm{O}\end{array}$

Hence, the correct answer is option: 'D'.

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