Q14 / 120 · VITEEE 2009 · Chemistry

$\mathrm{SiCl}_{4}$ on hydrolysis forms ' $\mathrm{X}$ ' and $\mathrm{HCl}$. Compound ' $\mathrm{X}$ ' loses water at $1000^{\circ} \mathrm{C}$ and gives 'Y'. Compounds ' $\mathrm{X}$ ' and ' $\mathrm{Y}$ 'respectively are

  • A
    $\mathrm{H}_{2} \mathrm{SiCl}_{6}, \mathrm{SiO}_{2}$
  • B
    $\mathrm{H}_{4} \mathrm{SiO}_{4}, \mathrm{Si}$
  • C
    $\mathrm{SiO}_{2}, \mathrm{Si}$
  • Correct answer
    D
    $\mathrm{H}_{4} \mathrm{SiO}_{4}, \mathrm{SiO}_{2}$

Solution

$$ \mathrm{SiCl}_{4}+4 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{H}_{4} \mathrm{SiO}_{4}+4 \mathrm{HCl} $$ $\mathrm{H}_{4} \mathrm{SiO}_{4} \underset{1000^{\circ} \mathrm{C}}{\stackrel{\Delta}{\mathrm{SiO}}} \mathrm{SiO}_{2}+2 \mathrm{H}_{2} \mathrm{O}$

Hence, the correct answer is option: 'D'.

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