Q28 / 180 · KCET 2022 · Chemistry

$\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$ on heating liberates a gas. The same gas will be obtained by

  • Correct answer
    A
    heating $\mathrm{NH}_4 \mathrm{NO}_2$
  • B
    treating $\mathrm{H}_2 \mathrm{O}_2$ with $\mathrm{NaNO}_2$
  • C
    treating $\mathrm{Mg}_3 \mathrm{~N}_2$ with $\mathrm{H}_2 \mathrm{O}$
  • D
    heating $\mathrm{NH}_4 \mathrm{NO}_3$

Solution

$\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$ and $\mathrm{NH}_4 \mathrm{NO}_2$ both on heating liberate nitrogen gas. The reaction involve are as follows $$ \begin{gathered} \left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7 \stackrel{\Delta \cdot}{\longrightarrow} \mathrm{N}_2 \uparrow+\mathrm{Cr}_2 \mathrm{O}_3+4 \mathrm{H}_2 \mathrm{O} . \\ \mathrm{NH}_4 \mathrm{NO}_3 \longrightarrow \mathrm{N}_2 \mathrm{O}+2 \mathrm{H}_2 \mathrm{O} \end{gathered} $$

Hence, the correct answer is option: 'A'.

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