Q72 / 180 · NEET 2020 (Phase 1) · Chemistry

On electrolysis of dil. sulphuric acid using Platinum Pt electrode, the product obtained at anode will be

  • Correct answer
    A
    Oxygen gas
  • B
    H2S gas
  • C
    SO2 gas
  • D
    Hydrogen gas

Solution

Dissociation of sulfuric acid, \(\mathrm{H}_2 \mathrm{SO}_4 \rightarrow 2 \mathrm{H}^{+}(\mathrm{aq})+\mathrm{SO}_4^{-2}(\mathrm{aq})\) Disssociation of water, \(\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{H}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})\) At Anode: \(4 \mathrm{OH}^{-} \rightarrow 2 \mathrm{H}_2 \mathrm{O}^{+}(\mathrm{l})+\mathrm{O}_2(\mathrm{~g})+4 \mathrm{e}^{-}\) At Cathode: \(2 \mathrm{H}^{+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2(\mathrm{~g})\)

Hence, the correct answer is option: 'A'.

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