On a line with direction cosines $l, \mathrm{~m}, \mathrm{n}, \mathrm{A}\left(\mathrm{x}_1, \mathrm{y}_1, \mathrm{z}_1\right)$ is a fixed point. If $\mathrm{B}=\left(\mathrm{x}_1+4 \mathrm{k} l, \mathrm{y}_1+4 \mathrm{~km}, \mathrm{z}_1+4 \mathrm{kn}\right)$ and $\mathrm{C}=\left(\mathrm{x}_1+\mathrm{k} l, \mathrm{y}_1+\mathrm{km}, \mathrm{z}_1+\mathrm{kn}\right)(\mathrm{k}>0)$ then the ratio in which the point B divides the line segment joining A and C is

• A

  $1: 2$
• B

  $1:-4$
• Correct answer
  C

  $4:-3$
• D

  $4: 3$

Hence, the correct answer is option: 'C'.