Q6 / 200 · TS EAMCET 2002 · Chemistry

$4 \mathrm{~g}$ of an ideal gas occupies $5.6035 \mathrm{~L}$ of volume at $546 \mathrm{~K}$ and 2 atmosphere pressure. What is its molecular weight?

  • A
    $4$
  • Correct answer
    B
    $16$
  • C
    $32$
  • D
    $64$

Solution

$\begin{aligned} & W=4 \mathrm{~g}, V=5.6035 \mathrm{~L}, T=546 \mathrm{~K}, P=2 \mathrm{~atm} \\ & \\ & \qquad \frac{M}{W}=\frac{R T}{P V} \quad\left(\because n=\frac{W}{M}\right) \\ & \frac{M}{4}=\frac{0.0821 \times 546}{2 \times 5.6035} \\ & \therefore \quad M=16\end{aligned}$

Hence, the correct answer is option: 'B'.

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