Q21 / 180 · COMEDK 2019 · Chemistry

$0.5 \mathrm{~g}$ of an acid is neutralised by $40 \mathrm{cc}$ of $0.125 \mathrm{~N} \mathrm{NaOH}$. The equivalent mass of the acid is

  • A
    50
  • Correct answer
    B
    100
  • C
    40
  • D
    80

Solution

Equivalent moles of $\mathrm{NaOH}=$ Equivalent moles of acid $N_{1} V_{1}=\frac{\text { Weight }}{\text { Equivalent mass }}$ $40 \times 10^{-3} \times 0.125=\frac{0.5}{\text { Equivalent mass }}$ $\therefore$ Equivalent mass of acid $=100$

Hence, the correct answer is option: 'B'.

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