Q38 / 125 · BITSAT 2012 · Chemistry

$0.45 \mathrm{~g}$ of acid molecular weight 90 is neutralised by $20 \mathrm{ml}$ of $0.5 \mathrm{~N}$ caustic potash. The basicity of acid is

  • A
    1
  • Correct answer
    B
    2
  • C
    3
  • D
    4

Solution

Eq. of acid = Eq of base, $\begin{array}{l} \therefore \frac{0.45}{\mathrm{E} \cdot \mathrm{wt}}=\frac{20 \times 0.5}{1000}=\mathrm{E} \mathrm{wt}=45 \\ \text { Basicity }=\frac{\mathrm{M} \cdot \mathrm{wt}}{\mathrm{E} \cdot \mathrm{wt}}=\frac{90}{45}=2 \end{array}$

Hence, the correct answer is option: 'B'.

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