Q60 / 180 · AIIMS 2010 · Chemistry

$100 \mathrm{~cm}^3$ of a given sample of $\mathrm{H}_2 \mathrm{O}_2$ gives $1000 \mathrm{~cm}^3$ of $\mathrm{O}_2$ at S.T.P. The given sample is

  • A
    $10 \% \mathrm{H}_2 \mathrm{O}_2$
  • B
    $90 \% \mathrm{H}_2 \mathrm{O}_2$
  • Correct answer
    C
    10 volume $\mathrm{H}_2 \mathrm{O}_2$
  • D
    100 volume $\mathrm{H}_2 \mathrm{O}_2$

Solution

$$ \begin{gathered} 2 \mathrm{H}_2 \mathrm{O}_2 \longrightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2 \\ 100 \mathrm{~mL} \\ 1000 \mathrm{~mL} \end{gathered} $$ or $1 \mathrm{~mL}$ of $\mathrm{H}_2 \mathrm{O}_2$ will give $10 \mathrm{~mL}$ of $\mathrm{O}_2$ at $\mathrm{STP}$ Thus its volume strength is 10 volume.

Hence, the correct answer is option: 'C'.

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