Q14 / 160 · AP EAMCET 2019 (23 Apr Shift 1) · Chemistry

Observe the following statements regarding \(\mathrm{C}_{60}\). i. All carbons are \(s p^2\)-hybridised. ii. It contains 12 rings of five carbons each and 20 rings of six carbons each. iii. It is a non-aromatic compound. iv. It is pure form of carbon. v. \(\mathrm{C}-\mathrm{C}\) bond lengths in it are 143.5 and \(138.3 \mathrm{pm}\). vi. It is prepared by heating graphite in an electric arc in the presence of oxygen. The correct statements are

  • A
    i, ii, iii, iv, v
  • Correct answer
    B
    i, ii, iv, v only
  • C
    i, ii, iv, vi only
  • D
    i, ii, iii only

Solution

In \(\mathrm{C}_{60}\), all carbon atoms are \(s p^2\)-hybridised. It contains 12 rings of five carbon each and 20 rings of six carbon each. It is anti-aromatic with spherically surrounded by \(\pi\)-electrons. It is a pure form of carbon. \(\mathrm{C}-\mathrm{C}\) bond length in it are 143.5 and \(138.3 \mathrm{pm}\). It is prepared by heating graphite in an electric arc under inert condition (He gas). Thus, statements (i), (ii), (iv) and (v) are correct.

Hence, the correct answer is option: 'B'.

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