Q84 / 160 · AP EAMCET 2022 (06 Jul Shift 2) · Mathematics

Number of triangle formed by the lines $x-y+3=0,2 x-y+3=0,3 x-y+2=0$ and $x+y-3=0$ is

  • Correct answer
    A
    4
  • B
    6
  • C
    3
  • D
    2

Solution

Slope of line $x-y+3=0$ is 1 . Slope of line $2 x-y+3=0$ is 2 . Slope of line $3 x-y+2=0$ is 3 . Slope of line $x+y-3=0$ is -1 . As the slope of lines are different, there are 4 concurrent lines. Number of triangles formed by these lines $$ ={ }^4 C_3=4 $$

Hence, the correct answer is option: 'A'.

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