Q36 / 83 · NTA Abhyas (JEE Main) 2020 · Mathematics · Trigonometric Equations

Number of solutions of 2sin(|x|)=3|cosx| in [ −π,π ], is equal to

Correct answer: 4

Solution

In the interval –π, π all the values of sin|x| are positive as well as |cosx|
Hence in –π, π, equation gets reduced to, 

2sin⁡x=3cos⁡x
Taking log on both sides,
sin⁡xlog⁡2=cos⁡xlog⁡3
⇒ tan⁡x=log⁡3/log⁡2 , value of tanx are positive in 1st and 3rd quadrant and negative in 2nd and 4th quadrant but positive for tan⁡x in all the values of x in –π, π.

Hence, tanx will repeat its value in all 4 quadrants, so the number of solutions are 4 .

Hence, the correct answer is 4.

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