Q67 / 200 · NEET 2008 (Screening) · Chemistry

Number of moles of $\mathrm{MnO}_4^{-}$required to oxidise one mole of ferrous oxalate completely in acidic medium will be

  • Correct answer
    A
    0.6 mole
  • B
    0.4 mole
  • C
    7.5 moles
  • D
    0.2 mole

Solution

Key Idea : $\mathrm{MnO}_4^{-}+5 \mathrm{C}_2 \mathrm{O}_4^{2-}+24 \mathrm{H}^{+} \longrightarrow 3 \mathrm{Mn}^{2+}+10 \mathrm{CO}_2+12 \mathrm{H}_2 \mathrm{O}$ $\because$ Number of moles of $\mathrm{MnO}_4^{-}$required to oxidise 5 moles of $\mathrm{C}_2 \mathrm{O}_4^{2-}=3$ $\therefore$ Number of moles of $\mathrm{MnO}_4^{-}$required to oxidise 1 mole of $\mathrm{C}_2 \mathrm{O}_4^{2-}=\frac{3}{5} =0.6 \mathrm{~mol}$

Hence, the correct answer is option: 'A'.

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