Q26 / 160 · AP EAMCET 2018 (24 Apr Shift 1) · Chemistry

Nitrous acid was disproportionated to form water, $\mathrm{HNO}_3$ and $X$. In another reaction, sodium nitrite was reacted with $\mathrm{H}_2 \mathrm{SO}_4$ to form $\mathrm{NaHSO}_4, \mathrm{HNO}_3$, water and $Y$. What are $X$ and $Y$ respectively?

  • A
    $\mathrm{NO}, \mathrm{N}_2 \mathrm{O}_3$
  • Correct answer
    B
    NO, NO
  • C
    $\mathrm{N}_2 \mathrm{O}, \mathrm{NO}_2$
  • D
    $\mathrm{NO}_2, \mathrm{~N}_2 \mathrm{O}_5$

Solution

Nitrous acid was disproportionated to form water, $\mathrm{HNO}_3$ and $\mathrm{NO}$. In another reaction, sodium nitrite was reacted with $\mathrm{H}_2 \mathrm{SO}_4$ to form $\mathrm{NaHSO}_4$, $\mathrm{HNO}_3$, water and NO. $$ \begin{aligned} & 3 \mathrm{HNO}_2 \longrightarrow \mathrm{HNO}_3+\mathrm{H}_2 \mathrm{O}+2 \mathrm{NO} \\ & 2 \mathrm{NaNO}_2+\mathrm{H}_2 \mathrm{SO}_4 \longrightarrow \mathrm{NaHSO}_4+\mathrm{HNO}_3+\mathrm{H}_2 \mathrm{O}+\mathrm{NO} \end{aligned} $$

Hence, the correct answer is option: 'B'.

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