Nitrogen forms five stable oxides with oxygen of the formula N_2 O, NO, N_2 O_3, ~N_2 O_4 and N_2 O_5 . The formation of these oxides explains fully the

Correct answer: (C) law of multiple proportion.. The weight of oxygen which combine with the fixed weight of nitrogen (=28 ~g) in N_2 O, NO, N_2 O_3 , N_2 O_4 and N_2 O_5 are 16,32,48,64,80 ~g respectively. They are in the ratio 1: 2: 3: 4: 5 . This proves the law of multiple proportion.

Q36 / 180 · COMEDK 2024 (Memory Based) · Chemistry

Nitrogen forms five stable oxides with oxygen of the formula $\mathrm{N}_2 \mathrm{O}, \mathrm{NO}, \mathrm{N}_2 \mathrm{O}_3, \mathrm{~N}_2 \mathrm{O}_4$ and $\mathrm{N}_2 \mathrm{O}_5$. The formation of these oxides explains fully the

A
law of definite proportion.
B
law of partial pressure.
Correct answer
C
law of multiple proportion.
D
law of reciprocal proportion.

Solution

The weight of oxygen which combine with the fixed weight of nitrogen $(=28 \mathrm{~g})$ in $\mathrm{N}_2 \mathrm{O}, \mathrm{NO}, \mathrm{N}_2 \mathrm{O}_3$, $\mathrm{N}_2 \mathrm{O}_4$ and $\mathrm{N}_2 \mathrm{O}_5$ are $16,32,48,64,80 \mathrm{~g}$ respectively. They are in the ratio $1: 2: 3: 4: 5$. This proves the law of multiple proportion.

Hence, the correct answer is option: 'C'.

Nitrogen forms five stable oxides with oxygen of the formula $\mathrm{N}_2 \mathrm{O}, \mathrm{NO}, \mathrm{N}_2 \mathrm{O}_3, \mathrm{~N}_2 \mathrm{O}_4$ and $\mathrm{N}_2 \mathrm{O}_5$. The formation of these oxides explains fully the

Solution

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