Nitrobenzene on reduction using zinc in alkaline medium results in $X$. The number of $\operatorname{sigma}(\sigma)$ and pi $(\pi)$ bonds in $X$ is

• A

  $24 \sigma, 7 \pi$
• B

  $24 \sigma, 6 \pi$
• C

  $27 \sigma, 7 \pi$
• Correct answer
  D

  $27 \sigma, 6 \pi$

Solution

Nitrobenzene on reduction using zinc in alkaline medium gives hydrazobenzene.
Hydrazobenzene $(X)$ contains $27 \sigma$ and $6 \pi$ bonds.

Hence, the correct answer is option: 'D'.