Q4 / 90 · JEE Main 2018 (15 Apr) · Chemistry

N2O5 decomposes to NO2 and O2 follows the first order kinetics. After 50 minutes, the pressure inside the vessel increases from 50 mm Hg to 87.5 mm Hg. The pressure of the gaseous mixture after 100 minutes at constant temperature will be:

  • A
    136.5 mm Hg
  • Correct answer
    B
    106.25 mm Hg
  • C
    175.0 mm Hg
  • D
    116.25 mm Hg

Solution

          N2O5→2NO2+12O2t=0          50          0         0t=50mins  50-p1     2p1     p12t=100mins   50-p2    2p2      p22

50-p1+2p1+p12=87.5

50+3p12=87.5

3p12=37.5

p1=37.5×23=25

50 minutes is half-life period.

For 100 minutes ( half-life 2)

50-p2=12.5

p2=37.5 mm Hg

Total pressure at 100 minutes.

=50-p2+2 p2+p22

50+3p22=50+32×37.5

=50+56.25

=106.25 mm of Hg.

Hence, the correct answer is option: 'B'.

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