Q46 / 150 · MHT CET 2009 · Chemistry
Most basic hydroxide among the following is
- A$\mathrm{Lu}(\mathrm{OH})_{3}$
- B$\mathrm{Eu}(\mathrm{OH})_{3}$
- C$\mathrm{Yb}(\mathrm{OH})_{3}$
- Correct answerD$\mathrm{Ce}(\mathrm{OH})_{3}$
Solution
Due to lanthanide contraction, the size of $M^{3+}$ ions [ie, $\mathrm{Lu}^{3+}, \mathrm{Eu}^{3+}, \mathrm{Yb}^{3+}$ and $\mathrm{Ce}^{3+}$ ] decreases
and thus, the basic strength of their hydroxides decreases.
The order of size of given $M^{3+}$ ions is $\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Yb}^{3+}>\mathrm{Lu}^{3+}$
$\therefore$ The order of basic strength of hydroxides is $\mathrm{Ce}(\mathrm{OH})_{3}>\mathrm{Eu}(\mathrm{OH})_{3}>\mathrm{Yb}(\mathrm{OH})_{3}>\mathrm{Lu}(\mathrm{OH})_{3}$
(most basic)
Hence, the correct answer is option: 'D'.