Q119 / 150 · MHT CET 2009 · Physics
Moment of inertia of a rod of mass $M$ and length $L$ about an axis passing through a point midway between centre and end is
- A$\frac{M L^{2}}{6}$
- B$\frac{M L^{2}}{12}$
- C$\frac{7 M L^{2}}{24}$
- Correct answerD$\frac{7 M L^{2}}{48}$
Solution

$$ \begin{array}{l} =\frac{M L^{2}}{12}+M\left[\frac{L}{4}\right]^{2} \\ =\frac{M L^{2}}{12}+\frac{M L^{2}}{16}=\frac{7 M L^{2}}{48} \end{array} $$
Hence, the correct answer is option: 'D'.