Q119 / 150 · MHT CET 2009 · Physics

Moment of inertia of a rod of mass $M$ and length $L$ about an axis passing through a point midway between centre and end is

  • A
    $\frac{M L^{2}}{6}$
  • B
    $\frac{M L^{2}}{12}$
  • C
    $\frac{7 M L^{2}}{24}$
  • Correct answer
    D
    $\frac{7 M L^{2}}{48}$

Solution

Figure
$$ \begin{array}{l} =\frac{M L^{2}}{12}+M\left[\frac{L}{4}\right]^{2} \\ =\frac{M L^{2}}{12}+\frac{M L^{2}}{16}=\frac{7 M L^{2}}{48} \end{array} $$

Hence, the correct answer is option: 'D'.

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