Q98 / 180 · AIIMS 2004 · Physics

$N$ moles of a monoatomic gas is carried round the reversible rectangular cycle $A B C D A$ as shown in the diagram. The temperature at $A$ is $T$. The thermodynamic efficiency of the cycle is Figure

  • A
    $15 \%$
  • Correct answer
    B
    $50 \%$
  • C
    $20 \%$
  • D
    $25 \%$.

Solution

At $A$, temperature $=T_0$, volume $=V_0$, pressure $-P_0$ for $n$ moles of monoatomic gas. At $A, P_0 V_0=n R T_0$ (cold) At $B, 2 P_0 V_0=n R T_{\text {high }}^{\prime} \Rightarrow T^{\prime}=2 T_0$ Maximum thermal efficiency of the reversible engine of this Carnot's cycle $$ =\eta=1-\frac{T_C}{T_h}=1-\frac{T_0}{2 T_0}=\frac{1}{2}=50 \% . $$

Hence, the correct answer is option: 'B'.

Relevant Questions