Molar ionic conductivities of divalent cation and anion are 57 ~S ~cm^2 ~mol^-1 and 73 ~S ~cm^2 ~mol^-1 respectively. The molar conductivity of solution of an electrolyte with the above cation and anion will be :

Correct answer: (C) 130 ~S ~cm^2 ~mol^-1. Λ_C^+2=57 Scm^2 ~mol^-1 Λ_A^+2=73 Scm^2 ~mol^-1 Λ_Solution =λ_C^+2+Λ_A^-2 =57+73=130

Q11 / 90 · JEE Main 2024 (05 Apr Shift 1) · Chemistry

Molar ionic conductivities of divalent cation and anion are $57 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ and $73 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ respectively. The molar conductivity of solution of an electrolyte with the above cation and anion will be :

A
$187 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
B
$260 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
Correct answer
C
$130 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
D
$65 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$

Solution

$\begin{aligned} & \Lambda_{\mathrm{C}}^{+2}=57 \mathrm{Scm}^2 \mathrm{~mol}^{-1} \\ & \Lambda_{\mathrm{A}}^{+2}=73 \mathrm{Scm}^2 \mathrm{~mol}^{-1} \\ & \Lambda_{\text {Solution }}=\lambda_{\mathrm{C}}^{+2}+\Lambda_{\mathrm{A}}^{-2} \\ & =57+73=130\end{aligned}$

Hence, the correct answer is option: 'C'.

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Molar ionic conductivities of divalent cation and anion are \(57 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) and \(73 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) respectively. The molar conductivity of solution of an electrolyte with the above cation and anion will be :

Solution

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