Molar conductivity of a solution of an electrolyte $\mathrm{A}{\mathrm{B}}_3$ is $150$ $\mathrm{S}\mathrm{c}{\mathrm{m}}^2\mathrm{m}\mathrm{o}{\mathrm{l}}^{-1}$ . If it ionizes as ${\text{AB}}_3\to {\text{A}}^{3+}+3{\text{B}}^{-}$ , its equivalent conductivity will be

• A

  $150\mathrm{}(\mathrm{i}\mathrm{n}$ $\mathrm{S}\mathrm{c}{\mathrm{m}}^2\mathrm{e}{\mathrm{q}}^{-1})$
• B

  $75\mathrm{}(\mathrm{i}\mathrm{n}$ $\mathrm{S}\mathrm{c}{\mathrm{m}}^2\mathrm{e}{\mathrm{q}}^{-1})$
• Correct answer
  C

  $50\mathrm{}(\mathrm{i}\mathrm{n}$ $\mathrm{S}\mathrm{c}{\mathrm{m}}^2\mathrm{e}{\mathrm{q}}^{-1})$
• D

  $80\mathrm{}(\mathrm{i}\mathrm{n}$ $\mathrm{S}\mathrm{c}{\mathrm{m}}^2\mathrm{e}{\mathrm{q}}^{-1}$ )

Hence, the correct answer is option: 'C'.