Maximum value of $\mathrm{Z}=100 x+70 y$ Subject to $2 x \geq 4, y \leq 3, x+y \leq 8, x, y \geq 0$ is

The feasible region lies on the origin side of $y=3$ and $x+y=8$, and on non-origin side of $2 x=4$, in the first quadrant.
The corner points of the feasible region are $\mathrm{A}(2,0), \mathrm{B}(8,0), \mathrm{C}(5,3)$ and $\mathrm{D}(2,3)$. $\mathrm{Z}=100 x+70 y$ At A(2, 0), Z= 200 At B( 8,0$), Z=800$ At C(5,3), Z= 710 At D(2, 3), Z= 410 $\therefore \quad$ Maximum value of $Z$ is 800 .