Q2 / 160 · AP EAMCET 2022 (05 Jul Shift 2) · Chemistry
Maximum number of electrons possible with spin quantum number $+\frac{1}{2}$ with principal quantum number $\mathrm{n}=4$ in an atom is
- Correct answerA$16$
- B$9$
- C$4$
- D$25$
Solution
Maximum number of electrons
$=2 n^2=2 \times 4 \times 4=32($ when $n=4)$
Half of the electrons have $\left(+\frac{1}{2}\right)$ spin, i.e., 16
Hence, the correct answer is option: 'A'.