Q2 / 160 · AP EAMCET 2022 (05 Jul Shift 2) · Chemistry

Maximum number of electrons possible with spin quantum number $+\frac{1}{2}$ with principal quantum number $\mathrm{n}=4$ in an atom is

  • Correct answer
    A
    $16$
  • B
    $9$
  • C
    $4$
  • D
    $25$

Solution

Maximum number of electrons $=2 n^2=2 \times 4 \times 4=32($ when $n=4)$ Half of the electrons have $\left(+\frac{1}{2}\right)$ spin, i.e., 16

Hence, the correct answer is option: 'A'.

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