Q15 / 54 · JEE Advanced 2022 (Paper 1) · Chemistry

Match the rate expressions in LIST-I for the decomposition of \(\mathrm{X}\) with the corresponding profiles provided in LIST-II. \(X_s\) and \(\mathrm{k}\) are constants having appropriate units. Figure

  • Correct answer
    A
    I→P;II→Q;III→S;IV→T
  • B
    I→R;II→S;III→S;IV→T
  • C
    I→P;II→Q;III→Q;IV→R
  • D
    I→R;II→S;III→Q;IV→R

Solution

I rate =kXXS+X

Case-1: X>>Xs;X+Xs≈X

rate =kXX=k    (Zero order w.r.t. X)

I→P,S

Figure
Figure

 

Case-2: X≪Xs;X+Xs≈Xs

∴ rate =kXXS=k'X   (1st order w.r.t. X)

∴  I→Q,T

Case-3: X≈XS

rate =kXXs+X

In this case curve-R given in List-II will match.

∴ I→P,Q,R,S,T  (The graph of half-life should start from origin)

II rate =kXXS+X

∵ X≪XS

∴ Xs+X≈Xs

∴  rate =kXXS=k'X  (1st order w.r.t. X)

∴ II→Q,T

Figure
Figure

III  rate =kXXs+X

∵ X>>Xs

∴ Xs+X≈X

∴  rate =kXX=k   (Zero order w.r.t. X)

∴  III→P,S

IV rate =kX2Xs+X

∵ X>>XS

∴ XS+X≈X

∴  rate =kX2X=kX   (1st order w.r.t. X)

∴ IV→Q,T

Hence, the correct answer is option: 'A'.

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