Q61 / 75 · JEE Main 2026 (24 January Shift 1) · Physics

Match the LIST-I with LIST-II
\(\begin{array}{||c|l||c|l||} \hline & \text{List-I} & & \text{List-II} \\ \hline \text{A.} & \text{Magnetic induction} & \text{I.} & \mathrm{M\,L\,T^{-2}\,A^{-2}} \\ \hline \text{B.} & \text{Magnetic flux} & \text{II.} & \mathrm{M\,L^{2}\,T^{-2}\,A^{-2}} \\ \hline \text{C.} & \text{Magnetic permeability} & \text{III.} & \mathrm{M\,L^{0}\,T^{-2}\,A^{-1}} \\ \hline \text{D.} & \text{Self inductance} & \text{IV.} & \mathrm{M\,L^{2}\,T^{-2}\,A^{-1}} \\ \hline \end{array}\)
Choose the correct answer from the options given below:

  • A
    A-III, B-IV, C-II, D-I
  • Correct answer
    B
    A-III, B-IV, C-I, D-II
  • C
    A-IV, B-III, C-I, D-II
  • D
    A-I, B-III, C-IV, D-II

Solution

Match physical quantities with dimensional formulas using fundamental principles.
Magnetic Induction (A): From $F = qvB$, $[B] = \frac{MLT^{-2}}{AT \cdot LT^{-1}} = MT^{-2}A^{-1} = $ III
Magnetic Flux (B): $\Phi = BA$, $[\Phi] = MT^{-2}A^{-1} \cdot L^2 = ML^2T^{-2}A^{-1} = $ IV
Magnetic Permeability (C): From $B = \mu H$ with $[H] = ALT^{-1}$, $[\mu] = \frac{MT^{-2}A^{-1}}{AL^{-1}T^{-1}} = MLT^{-2}A^{-2} = $ I
Self Inductance (D): From $\varepsilon = L\frac{dI}{dt}$, $[L] = \frac{ML^2T^{-3}A^{-1}}{AT^{-1}} = ML^2T^{-2}A^{-2} = $ II
Correct matching: A-III, B-IV, C-I, D-II

Hence, the correct answer is option: 'B'.

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