Match the following: $\begin{array}{|l|c|}\hline \text{List-I} & \text{List-II} \\ \text{(Amine)} & \text{(pK valine)} \\ \hline \text{A. N,N-Dimethyl aniline} & \text{I. } 9.30 \\ \hline \text{B. Aniline} & \text{II. } 8.92 \\ \hline \text{C. N-Ethylethanamine} & \text{III. } 9.38 \\ \hline \text{D. N-Methylaniline} & \text{IV. } 3.00 \\ \hline\end{array}$ The correct answer is

• Correct answer
  A

  A-II, B-III, C-IV, D-I
• B

  A-II, B-IV, C-III, D-I
• C

  A-III, B-IV, C-I, D-II
• D

  A-IV, B-III, C-II, D-I

Solution

A lower $\mathrm{pK}_{\mathrm{b}}$ value indicates a stronger base. In 'C' presence of two alkyl group make it stronger base as compare of $\mathrm{A}, \mathrm{C}$ and D in which resonance is present. In 'A' two methyl group present due to + I effect of methyl group more electron density is on N as co

Hence, the correct answer is option: 'A'.