Match the following columns.
Codes $\begin{array}{llll}A & B & C & D\end{array}$

The potential energy of satellite at distance $r$ from earth is $$ U=\frac{-G M m}{r} $$ So, it is always negative as it is due to attractive gravitation force of earth's field. The kinetic energy of satellite is $$ K=\frac{G M m}{2 r} $$ It is always positive. The total energy of satellite is $$ \begin{aligned} \mathrm{TE} & =K+U=\frac{G M m}{2 r}-\frac{G M m}{r} \\ & =-\frac{G M m}{2 r} \end{aligned} $$ which is negative. The gravitation potential energy of satellite at infinity is $$ U=-\frac{G M m}{r}=-\frac{G M m}{\infty}=0 $$ So, the correct match is $\mathrm{A} \rightarrow \mathrm{II}, \mathrm{B} \rightarrow \mathrm{II}, \mathrm{C} \rightarrow \mathrm{I}, \mathrm{D} \rightarrow$ III. No option is correct.