Q38 / 180 · COMEDK 2023 (Evening Shift) · Chemistry
Match the following characteristics of transition metals given in Column I with the examples listed in Column II
S.No. Characteristic properties S.No. Examples W Chemically inert, non-stoichiometric compound A $WO_3$ X Higher oxidation states are more stable B $TiCl_4$ Y Due to inert pair effect, lower oxidation state is more stable C $Mn_4N$ Z Colourless compound of transition metal D $SnCl_2$
| S.No. | Characteristic properties | S.No. | Examples |
|---|---|---|---|
| W | Chemically inert, non-stoichiometric compound | A | $WO_3$ |
| X | Higher oxidation states are more stable | B | $TiCl_4$ |
| Y | Due to inert pair effect, lower oxidation state is more stable | C | $Mn_4N$ |
| Z | Colourless compound of transition metal | D | $SnCl_2$ |
- Correct answerA$\mathrm{W}=\mathrm{C} \quad \mathrm{X}=\mathrm{A} \quad \mathrm{Y}=\mathrm{D} \quad \mathrm{Z}=\mathrm{B}$
- B$\mathrm{W}=\mathrm{C} \quad \mathrm{X}=\mathrm{D} \quad \mathrm{Y}=\mathrm{A} \quad \mathrm{Z}=\mathrm{B}$
- C$\mathrm{W}=\mathrm{A} \quad \mathrm{X}=\mathrm{D} \quad \mathrm{Y}=\mathrm{C} \quad \mathrm{Z}=\mathrm{B}$
- D$\mathrm{W}=\mathrm{B} \quad \mathrm{X}=\mathrm{C} \quad \mathrm{Y}=\mathrm{D} \quad \mathrm{Z}=\mathrm{A}$
Solution
W: Chemically inert, non-stoichiometric compound. Interstitial compounds like $\mathrm{Mn_4N}$ are non-stoichiometric and often chemically inert. Thus, W matches with C.
X: Higher oxidation states are more stable. In the case of $\mathrm{WO_3}$, tungsten is in its highest oxidation state of $+6$, which is the most stable state for group 6 elements. Thus, X matches with A.
Y: Due to inert pair effect, lower oxidation state is more stable. $\mathrm{SnCl_2}$ involves tin, which is a post-transition element where the inert pair effect makes the $+2$ state more stable than the $+4$ state. Thus, Y matches with D.
Z: Colourless compound of transition metal. $\mathrm{TiCl_4}$ contains $\mathrm{Ti^{4+}}$ ($d^0$ configuration), which is colourless. Thus, Z matches with B.
Answer: $\mathrm{W}=\mathrm{C} \quad \mathrm{X}=\mathrm{A} \quad \mathrm{Y}=\mathrm{D} \quad \mathrm{Z}=\mathrm{B}$
X: Higher oxidation states are more stable. In the case of $\mathrm{WO_3}$, tungsten is in its highest oxidation state of $+6$, which is the most stable state for group 6 elements. Thus, X matches with A.
Y: Due to inert pair effect, lower oxidation state is more stable. $\mathrm{SnCl_2}$ involves tin, which is a post-transition element where the inert pair effect makes the $+2$ state more stable than the $+4$ state. Thus, Y matches with D.
Z: Colourless compound of transition metal. $\mathrm{TiCl_4}$ contains $\mathrm{Ti^{4+}}$ ($d^0$ configuration), which is colourless. Thus, Z matches with B.
Answer: $\mathrm{W}=\mathrm{C} \quad \mathrm{X}=\mathrm{A} \quad \mathrm{Y}=\mathrm{D} \quad \mathrm{Z}=\mathrm{B}$
Hence, the correct answer is option: 'A'.