Q5 / 160 · AP EAMCET 2023 (18 May Shift 2) · Chemistry

Match the following \begin{array}{ll} \begin{array}{l} List- I \\ (Hybridisation) \end{array} & \begin{array}{l} List- II \\ (Shape) \end{array} \\ A. \mathrm{dsp}^2 & I. Square planar \\ B. \mathrm{sp}^3 & II. Tetrahedral \\ C. \mathrm{d}^2 \mathrm{sp}^3 & III. Octahedral \\ D. \mathrm{Sp}^3 \mathrm{~d} & IV. Trigonal bipyramidal \end{array}

  • A
    A-II, B-I, C-III, D-IV
  • Correct answer
    B
    A-I, B-II, C-III, D-IV
  • C
    A-III, B-IV, C-II, D-I
  • D
    A-IV, B-III, C-II, D-I

Solution

$\begin{aligned} & \mathrm{sp}^3-\text { tetrahedral } \\ & \mathrm{sp}^3 \mathrm{~d} \text { - trigonal bipyramidal } \\ & \mathrm{dsp}^3-\mathrm{square} \text { planar } \\ & \mathrm{sp}^3 \mathrm{~d}^2 / \mathrm{d}^2 \mathrm{sp}^3-\text { octahedral }\end{aligned}$

Hence, the correct answer is option: 'B'.

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