Q4 / 50 · Manipal (MET) 2023 · Chemistry
Match the complex given in column-I with their hybridisation given in column-II.


- A$\begin{array}{l|l}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D} \\ \hline \mathrm{1} & \mathrm{2} & \mathrm{3} & \mathrm{4}\end{array}$
- Correct answerB$\begin{array}{l|l}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D} \\ \hline \mathrm{2} & \mathrm{1} & \mathrm{4} & \mathrm{3}\end{array}$
- C$\begin{array}{l|l}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D} \\ \hline \mathrm{1} & \mathrm{3} & \mathrm{2} & \mathrm{4}\end{array}$
- D$\begin{array}{l|l}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D} \\ \hline \mathrm{2} & \mathrm{3} & \mathrm{1} & \mathrm{4}\end{array}$
Solution
$\left[\mathrm{Ni}(\mathrm{CO})_4\right]-s p^3$-hybridisation
$\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}-d s p^2$-hybridisation
$\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+}-s p^3 d^2$-hybridisation
$\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}-d^2 s p^3$-hybridisation
The correct answer is A-2, B-1, C-4, D-3.
Hence, the correct answer is option: 'B'.