Q17 / 60 · JEE Advanced 2013 (Paper 2) · Chemistry

Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using the code given below the lists :
 
 List - I   List - II 
 (A)  Figure  (P)  i HgOAc2; ii NaBH4
 (B)  ​Figure  (Q)  NaOEt
 (C)  Figure  (R)  Et-Br
 (D)  Figure  (S)  i BH3; ii H2O2/NaOH

  • A
    a-p;b-r;c-q;d-s;
  • B
    a-q;b-r;c-s;d-p;
  • Correct answer
    C
    a-q;b-r;c-p;d-s;
  • D
    a-q;b-p;c-r;d-s;

Solution

A tertiary alkyl halide with strong base undergoes elimination reaction, while a primary alkyl halide with t-butoxide gives ether by a substitution reaction. Alkenes undergo hydration (addition of water) by Hydroboration-Oxidation, giving anti-Markovnikov's products and by Oxymercuration-Demercuration, giving Markovnikov's products.Figure

Hence, the correct answer is option: 'C'.

More Alcohols Phenols and Ethers Questions