Match List-I with List-II :

	List-I (Name of ore/mineral)		List-I (Chemical formula)
a	Calamine	i	$\mathrm{ZnS}$
b	Malachite	ii	${\mathrm{FeCO}}_3$
c	Siderite	iii	${\mathrm{ZnCO}}_3$
d	Sphalerite	iv	${\mathrm{CuCO}}_3·\mathrm{Cu}(\mathrm{OH}{)}_2$

Choose the most appropriate answer from the options given below :

• A

  $\left(\mathrm{a}\right) - \left(\mathrm{iv}\right), \left(\mathrm{b}\right) - \left(\mathrm{iii}\right), \left(\mathrm{c}\right) - \left(\mathrm{i}\right), \left(\mathrm{d}\right) - \left(\mathrm{ii}\right)$
• B

  $\left(\mathrm{a}\right) - \left(\mathrm{iii}\right), \left(\mathrm{b}\right) - \left(\mathrm{ii}\right), \left(\mathrm{c}\right) - \left(\mathrm{iv}\right), \left(\mathrm{d}\right) - \left(\mathrm{i}\right)$
• C

  $(\mathrm{a}) -(\mathrm{iii}),(\mathrm{b})-(\mathrm{iv}),(\mathrm{c})-(\mathrm{i}),(\mathrm{d})-(\mathrm{ii})$
• Correct answer
  D

  $(\mathrm{a}) -(\mathrm{iii}), (\mathrm{b}) -(\mathrm{iv}),(\mathrm{c})-(\mathrm{ii}),(\mathrm{d})-(\mathrm{i})$

Hence, the correct answer is option: 'D'.