Q91 / 240 · KCET 2026 · Chemistry
Match List-I with List-II:
List-I (Element-Atomic number) List-II (Position in periodic table) (a) Ra – 88 (i) $4^{th}$ period, $13^{th}$ group (b) Ga – 31 (ii) $6^{th}$ period, $6^{th}$ group (c) W – 74 (iii) $5^{th}$ period, $10^{th}$ group (d) Pd – 46 (iv) $7^{th}$ period, $2^{nd}$ group
Choose the correct answer from the options given below.
| List-I (Element-Atomic number) | List-II (Position in periodic table) | ||
|---|---|---|---|
| (a) | Ra – 88 | (i) | $4^{th}$ period, $13^{th}$ group |
| (b) | Ga – 31 | (ii) | $6^{th}$ period, $6^{th}$ group |
| (c) | W – 74 | (iii) | $5^{th}$ period, $10^{th}$ group |
| (d) | Pd – 46 | (iv) | $7^{th}$ period, $2^{nd}$ group |
- Correct answerAa-iv, b-i, c-ii, d–iii
- Ba-i, b-ii, c-iii, d-iv
- Ca-iv, b-ii, c-iii, d–i
- Da-iii, b-iv, c-i, d-ii
Solution
The position of an element in the periodic table can be determined using its atomic number and the nearest preceding noble gas.
(a) Ra ($Z = 88$): The preceding noble gas is Radon (Rn, $Z = 86$), which belongs to the $6^{th}$ period and $18^{th}$ group. The next two electrons enter the $7s$ orbital. Thus, Ra belongs to the $7^{th}$ period and $2^{nd}$ group. (a) $\rightarrow$ (iv)
(b) Ga ($Z = 31$): The preceding noble gas is Argon (Ar, $Z = 18$), which belongs to the $3^{rd}$ period. The next electrons fill the $4s$, $3d$, and $4p$ orbitals. The group number is $31 - 18 = 13$. Thus, Ga belongs to the $4^{th}$ period and $13^{th}$ group. (b) $\rightarrow$ (i)
(c) W ($Z = 74$): The preceding noble gas is Xenon (Xe, $Z = 54$), which belongs to the $5^{th}$ period. The next electrons fill the $6s$, $4f$ (14 elements), and $5d$ orbitals. The group number is $74 - 54 - 14 = 6$. Thus, W belongs to the $6^{th}$ period and $6^{th}$ group. (c) $\rightarrow$ (ii)
(d) Pd ($Z = 46$): The preceding noble gas is Krypton (Kr, $Z = 36$), which belongs to the $4^{th}$ period. The next electrons fill the $5s$ and $4d$ orbitals. The group number is $46 - 36 = 10$. Thus, Pd belongs to the $5^{th}$ period and $10^{th}$ group. (d) $\rightarrow$ (iii)
The correct matching is a-iv, b-i, c-ii, d-iii.
Answer: a-iv, b-i, c-ii, d–iii
(a) Ra ($Z = 88$): The preceding noble gas is Radon (Rn, $Z = 86$), which belongs to the $6^{th}$ period and $18^{th}$ group. The next two electrons enter the $7s$ orbital. Thus, Ra belongs to the $7^{th}$ period and $2^{nd}$ group. (a) $\rightarrow$ (iv)
(b) Ga ($Z = 31$): The preceding noble gas is Argon (Ar, $Z = 18$), which belongs to the $3^{rd}$ period. The next electrons fill the $4s$, $3d$, and $4p$ orbitals. The group number is $31 - 18 = 13$. Thus, Ga belongs to the $4^{th}$ period and $13^{th}$ group. (b) $\rightarrow$ (i)
(c) W ($Z = 74$): The preceding noble gas is Xenon (Xe, $Z = 54$), which belongs to the $5^{th}$ period. The next electrons fill the $6s$, $4f$ (14 elements), and $5d$ orbitals. The group number is $74 - 54 - 14 = 6$. Thus, W belongs to the $6^{th}$ period and $6^{th}$ group. (c) $\rightarrow$ (ii)
(d) Pd ($Z = 46$): The preceding noble gas is Krypton (Kr, $Z = 36$), which belongs to the $4^{th}$ period. The next electrons fill the $5s$ and $4d$ orbitals. The group number is $46 - 36 = 10$. Thus, Pd belongs to the $5^{th}$ period and $10^{th}$ group. (d) $\rightarrow$ (iii)
The correct matching is a-iv, b-i, c-ii, d-iii.
Answer: a-iv, b-i, c-ii, d–iii
Hence, the correct answer is option: 'A'.