Match List-I with List-II. List-I List-II (A) Heat capacity of body (I) J kg^-1 (B) Specific heat capacity of body (II) JK^-1 (C) Latent heat (III) J kg^-1 ~K^-1 (D) Thermal conductivity (IV) Jm^-1 ~K^-1 ~s^-1 Choose the correct answer from the options given below :

Correct answer: (D) (A)-(II), (B)-(III), (C)-(I), (D)-(IV). C^′=(Δ Q)/(Δ T)=JK^-1 ~S=(Δ Q)/(m Δ T)=Jkg^-1 ~K^-1 ~L=(Δ Q)/m=Jkg^-1 Δ Q=(KA Δ T)/L ⇒ K=(Δ Q(L))/(A Δ T)=Jm^-1 ~K^-1 ~s^-1

Q73 / 75 · JEE Main 2025 (2 Apr Shift 2) · Physics

Match List-I with List-II.
$\begin{array}{ll} \text{List-I} & \text{List-II} \\ \text{(A) Heat capacity of body} & \text{(I) } \mathrm{J} \mathrm{kg}^{-1} \\ \text{(B) Specific heat capacity of body} & \text{(II) } \mathrm{JK}^{-1} \\ \text{(C) Latent heat} & \text{(III) } \mathrm{J} \mathrm{kg}^{-1} \mathrm{~K}^{-1} \\ \text{(D) Thermal conductivity} & \text{(IV) } \mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1} \end{array}$
Choose the correct answer from the options given below :

A
(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
B
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
C
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Correct answer
D
(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Solution

$\begin{aligned} & \mathrm{C}^{\prime}=\frac{\Delta \mathrm{Q}}{\Delta \mathrm{T}}=\mathrm{JK}^{-1} \\ & \mathrm{~S}=\frac{\Delta \mathrm{Q}}{\mathrm{m} \Delta \mathrm{T}}=\mathrm{Jkg}^{-1} \mathrm{~K}^{-1} \\ & \mathrm{~L}=\frac{\Delta \mathrm{Q}}{\mathrm{m}}=\mathrm{Jkg}^{-1} \\ & \Delta \mathrm{Q}=\frac{\mathrm{KA} \Delta \mathrm{T}}{\mathrm{L}} \Rightarrow \mathrm{K}=\frac{\Delta \mathrm{Q}(\mathrm{L})}{\mathrm{A} \Delta \mathrm{T}}=\mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1}\end{aligned}$

Hence, the correct answer is option: 'D'.

Solution

Relevant Questions