Q67 / 180 · NEET 2025 · Chemistry
Match List-I with List-II
$\begin{array}{|l|l|l|l|}\hline & \text{List-I (Mixture)} & & \text{List-II (Method of Separation)} \\\hline A. & \mathrm{CHCl}_3+\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2 & I. & \text{Distillation under reduced pressure} \\\hline B. & \text{Crude oil in petroleum industry} & II. & \text{Steam distillation} \\\hline C. & \text{Glycerol from spent-lye} & III. & \text{Fractional distillation} \\\hline D. & \text{Aniline-water} & IV. & \text{Simple distillation} \\\hline\end{array}$
Choose the correct answer from the options given below :-
- Correct answerAA-IV, B-III, C-I, D-II
- BA-IV, B-III, C-II, D-I
- CA-III, B-IV, C-I, D-II
- DA-III, B-IV, C-II, D-I
Solution
Correct Match
$\begin{array}{|l|l|l|l|}\hline \mathrm{CHCl}_3+\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2 & \rightarrow & \text{Simple distillation} \\\hline \text{Crude oil in petroleum industry} & \rightarrow & \text{Fractional distillation (III)} \\\hline \text{Glycerol from} & \rightarrow & \text{Distillation under spent-lye reduced pressure (I)} \\\hline \text{Aniline-water} & \rightarrow & \text{Steam distillation (II)} \\\hline\end{array}$
Hence, the correct answer is option: 'A'.