Q2 / 90 · JEE Main 2024 (05 Apr Shift 2) · Chemistry

Match List I with List II \(\begin{array}{llll} \text{List - I} & \text{List - II} \\ \text{(Pair of compounds)} & \text{(Isomerism)} \\ \text{(A) n-propanol and Isopropanol} & \text{(I) Metamerism} \\ \text{(B) Methoxypropane and ethoxyethane} & \text{(II) Chain Isomerism} \\ \text{(C) Propanone and propanal} & \text{(III) Position Isomerism} \\ \text{(D) Neopentane and Isopentane} & \text{(IV) Functional Isomerism} \\ \end{array}\) Choose the correct answer from the options given below :

  • A
    (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  • B
    (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
  • C
    (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
  • Correct answer
    D
    (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Solution

Figure
$\qquad$ $\Rightarrow$ Position isomersFigure
$\qquad$ $\Rightarrow$ MetamersFigure
$\qquad$ $\Rightarrow$ Functional isomersFigure
$\qquad$ $\Rightarrow$ Chain isomers

Hence, the correct answer is option: 'D'.

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