Q2 / 90 · JEE Main 2024 (05 Apr Shift 2) · Chemistry
Match List I with List II
\(\begin{array}{llll}
\text{List - I} & \text{List - II} \\
\text{(Pair of compounds)} & \text{(Isomerism)} \\
\text{(A) n-propanol and Isopropanol} & \text{(I) Metamerism} \\
\text{(B) Methoxypropane and ethoxyethane} & \text{(II) Chain Isomerism} \\
\text{(C) Propanone and propanal} & \text{(III) Position Isomerism} \\
\text{(D) Neopentane and Isopentane} & \text{(IV) Functional Isomerism} \\
\end{array}\)
Choose the correct answer from the options given below :
- A(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
- B(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
- C(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
- Correct answerD(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Solution

$\qquad$ $\Rightarrow$ Position isomers

$\qquad$ $\Rightarrow$ Metamers

$\qquad$ $\Rightarrow$ Functional isomers

$\qquad$ $\Rightarrow$ Chain isomers
Hence, the correct answer is option: 'D'.