Match List-I with List-II : \(\begin{array}{l|l} \text{List-I} & \text{List-II} \\ \text{(Compounds)} & \text{(Molecular formula)} \\ \hline \text { (a) Borax } & \text { (i) } \mathrm{NaBO}_2 \\ \text { (b) Kernite } & \text { (ii) } \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 4 \mathrm{H}_2 \mathrm{O} \\ \text { (c) Orthoboric acid } & \text { (iii) } \mathrm{H}_3 \mathrm{BO}_3 \\ \text { (d) Borax bead } & \text { (iv) } \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O} \end{array}\) Choose the correct answer from the options given below :

• Correct answer
  A

  (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
• B

  (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
• C

  (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
• D

  (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

Hence, the correct answer is option: 'A'.