Q17 / 90 · JEE Main 2024 (09 Apr Shift 2) · Chemistry
Match List I with List II
\(\begin{array}{|l|l|l|l|}
\hline & \text{ List - I (Element) } & & \text{List - II (Electronic configuration)} \\
\hline \text { A. } & \mathrm{N} & \text { I. } & {[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^5 \mathrm{AR}} \\
\hline \text { B. } & \mathrm{S} & \text { II. } & {[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^4} \\
\hline \text { C. } & \mathrm{Br} & \text { III. } & {[\mathrm{He}] 2 \mathrm{~s}^2 2 \mathrm{p}^3} \\
\hline \text { D. } & \mathrm{Kr} & \text { IV. } & {[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^6} \\
\hline
\end{array}\)
Choose the correct answer from the options given below:
- Correct answerAA-III, B-II, C-I, D-IV
- BA-II, B-I, C-IV, D-III
- CA-I, B-IV, C-III, D-II
- DA-IV, B-III, C-II, D-I
Solution
(A) ${ }_7 \mathrm{~N}:[\mathrm{He}] 2 \mathrm{~s}^2 2 \mathrm{p}^3$
(B) ${ }_{16} \mathrm{~S}:[\mathrm{Ne}] 2 \mathrm{~s}^2 3 \mathrm{p}^4$
(C) ${ }_{35} \mathrm{Br}:[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^5$
(D) ${ }_{36} \mathrm{Kr}:[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^6$
Hence, the correct answer is option: 'A'.