Q4 / 90 · JEE Main 2024 (09 Apr Shift 2) · Chemistry
Match List I with List II
\(\begin{array}{|l|l|c|l|}
\hline & \text{ List - I } & & \text{List - II} \\
\hline \text { A. } & \text { Melting Point }[\mathrm{K}] & \text { I. } & \mathrm{T} 1>\mathrm{In}>\mathrm{Ga}>\mathrm{A} 1>\mathrm{B} \\
\hline \text { B. } & \text { Ionic Radius }\left[\mathrm{M}^{+3} / \mathrm{pm}\right] & \text { II. } & \mathrm{B}>\mathrm{T} 1>\mathrm{A} 1 \approx \mathrm{Ga}>\mathrm{In} \\
\hline \text { C. } & \Delta_{\mathrm{i}} \mathrm{H}_1\left[\mathrm{~kJ} \mathrm{~mol}^{-1}\right] & \text { III. } & \mathrm{T} 1>\mathrm{In}>\mathrm{A} 1>\mathrm{Ga}>\mathrm{B} \\
\hline \text { D. } & \text { Atomic Radius }[\mathrm{pm}] & \text { IV. } & \mathrm{B}>\mathrm{A} 1>\mathrm{T} 1>\mathrm{In}>\mathrm{Ga} \\
\hline
\end{array}\)
Choose the correct answer from the options given below:
- AA-II, B-III, C-IV, D-I
- Correct answerBA-IV, B-I, C-II, D-III
- CA-I, B-II, C-III, D-IV
- DA-III, B-IV, C-I, D-II
Solution
Melting point : $\mathrm{B}>\mathrm{A} \ell>\mathrm{T} \ell>\mathrm{In}>\mathrm{Ga}$
Ionic radius $\left(\mathrm{M}^{+3} / \mathrm{pm}\right): \mathrm{T} \ell>\mathrm{In}>\mathrm{Ga}>\mathrm{A} \ell>\mathrm{B}$
$\left(\Delta_{\mathrm{IE}} \mathrm{H}\right)_1\left[\frac{\mathrm{kJ}}{\mathrm{mol}}\right]: \mathrm{B}>\mathrm{T} \ell>\mathrm{A} \ell \approx \mathrm{Ga}>\mathrm{In}$
Atomic radius (in $\mathrm{pm}$ ) : $\mathrm{T} \ell>\mathrm{In}>\mathrm{A} \ell>\mathrm{Ga}>\mathrm{B}$
Atomic radius (in $\mathrm{pm}$ ) : $\mathrm{T} \ell>\mathrm{In}>\mathrm{A} \ell>\mathrm{Ga}>\mathrm{B}$
Hence, the correct answer is option: 'B'.