Q175 / 200 · NEET 2022 (Phase 2) · Zoology
Match List-I with List-II :
\(\begin{array}{|l|l|}
\hline \text { List - I } & \text { List - II } \\
\hline \text { (a) Bacteriophage } \phi \times 174 & \text { (i) } 48502 \text { base pairs } \\
\text { (b) Bacteriophage lambda } & \text { (ii) } 5386 \text { nucleotides } \\
\text { (c) Escherichia coli } & \text { (iii) } 3.3 \times 109 \text { base pairs } \\
\text { (d) Haploid content of human DNA } & \text { (iv) } 4.6 \times 106 \text { base pairs } \\
\hline
\end{array}\)
Choose the correct answer from the options given below:
- A(a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)
- B(a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
- Correct answerC(a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
- D(a) - (i), (b) - (ii), (c) - (iv), (d) - (iii)
Hence, the correct answer is option: 'C'.