Q175 / 200 · NEET 2022 (Phase 2) · Zoology

Match List-I with List-II : \(\begin{array}{|l|l|} \hline \text { List - I } & \text { List - II } \\ \hline \text { (a) Bacteriophage } \phi \times 174 & \text { (i) } 48502 \text { base pairs } \\ \text { (b) Bacteriophage lambda } & \text { (ii) } 5386 \text { nucleotides } \\ \text { (c) Escherichia coli } & \text { (iii) } 3.3 \times 109 \text { base pairs } \\ \text { (d) Haploid content of human DNA } & \text { (iv) } 4.6 \times 106 \text { base pairs } \\ \hline \end{array}\) Choose the correct answer from the options given below:

  • A
    (a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)
  • B
    (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
  • Correct answer
    C
    (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
  • D
    (a) - (i), (b) - (ii), (c) - (iv), (d) - (iii)

Hence, the correct answer is option: 'C'.

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