Q64 / 200 · NEET 2023 (Manipur) · Chemistry

Match List-I with List-II. \(\begin{array}{|c|l|c|l|} \hline & \text { List - I } & & \text { List - II } \\ \hline & \text { (Hydride) } & & \text { (Type of hydride) } \\ \hline(A) & \mathrm{NaH} & \text { (I) } & \text { Electron precise } \\ \hline \text { (B) } & \mathrm{PH}_3 & \text { (II) } & \text { Saline } \\ \hline \text { (C) } & \mathrm{GeH}_4 & \text { (III) } & \text { Metallic } \\ \hline \text { (D) } & \mathrm{LaH}_{2.87} & \text { (IV) } & \text { Electron rich } \\ \hline \end{array}\) Choose the correct answer from the options given below:

  • A
    $(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{IV})$
  • Correct answer
    B
    (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  • C
    (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  • D
    $(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})$

Solution

$\begin{array}{ll}\text { Hydride } & \text { Type of Hydride } \\ \mathrm{NaH} & \text { Saline or lonic hydride (Generally formed by s-block elements) } \\ \mathrm{PH}_3 & \text { Electron rich hydride (Elements of group 15-17 form such hydrides) } \\ \mathrm{GeH}_4 & \text { Electron precise (Elements of group } 14 \text { form such hydrides) } \\ \mathrm{LaH}_{2.87} & \text { Metallic or Non-stoichiometric hydrides (Formed by f block element) }\end{array}$

Hence, the correct answer is option: 'B'.

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