Q8 / 75 · JEE Main 2026 (21 January Shift 2) · Chemistry

Match List - I with List - II.
$\begin{array}{l} \text{List - I} & \text{List - II} \\ \text{Reagents} & \text{Reaction Name (Involving aldehydes)} \\ \text{A. } \mathrm{H}_{2}, \mathrm{Pd}-\mathrm{BaSO}_{4} & \text{I. Etard Reaction} \\ \text{B. } \mathrm{SnCl}_{2}, \mathrm{HCl} & \text{II. Rosenmund Reduction} \\ \text{C. } \mathrm{CrO}_{2} \mathrm{Cl}_{2}, \mathrm{CS}_{2} & \text{III. Gatterman - Koch Reaction} \\ \text{D. } \mathrm{CO}, \mathrm{HCl}, \text{ Anhyd. } \mathrm{AlCl}_{3} & \text{IV. Stephen Reaction} \end{array}$
Choose the correct answer from the options given below :

  • A
    A-IV, B-III, C-I, D-II
  • Correct answer
    B
    A-II, B-IV, C-I, D-III
  • C
    A-IV, B-I, C-II, D-III
  • D
    A-II, B-III, C-IV, D-I

Solution

Matching reagents with aldehyde reaction types:

A (H2, Pd-BaSO4) is the Lindlar/Rosenmund catalyst used in Rosenmund Reduction to convert acyl chlorides to aldehydes, matching with II.

B (SnCl2, HCl) is used in Stephen Reaction where nitriles are converted to aldehydes via imine intermediate, matching with IV.

C (CrO2Cl2, CS2) is Jones-like reagent used in Etard Reaction for oxidizing methyl groups on aromatic rings to aldehydes, matching with I.

D (CO, HCl, Anhyd. AlCl3) is the Gatterman-Koch Reaction which directly converts benzene to benzaldehyde using CO and AlCl3 catalyst, matching with III.

Therefore the correct matching is A-II, B-IV, C-I, D-III

Hence, the correct answer is option: 'B'.

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