Q74 / 90 · JEE Main 2024 (05 Apr Shift 2) · Physics
Match List-I with List-II :
$\begin{array}{|c|c|c|c|}
\hline & \text { List-I } & & \text { List-II } \\
\hline & \text { EM-Wave } & & \text { Wavelength Range } \\
\hline \text { (A) } & \text { Infra-red } & \text { (I) } & < 10^{-3} \mathrm{~nm} \\
\hline \text { (B) } & \text { Ultraviolet } & \text { (II) } & 400 \mathrm{~nm} \text { to } 1 \mathrm{~nm} \\
\hline \text { (C) } & \text { X-rays } S & \text { (III) } & 1 \mathrm{~mm} \text { to } 700 \mathrm{~nm} \\
\hline \text { (D) } & \text { Gamma rays } & \text { (IV) } & 1 \mathrm{~nm} \text { to } 10^{-3} \mathrm{~nm} \\
\hline
\end{array}$
- Correct answerA(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
- B(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
- C(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- D(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
Solution
Infrared is the least energetic thus having biggest wavelength $(\lambda) \&$ gamma rays are most energetic thus having smallest wavelength $(\lambda)$.
Hence, the correct answer is option: 'A'.