Q74 / 90 · JEE Main 2024 (05 Apr Shift 2) · Physics

Match List-I with List-II : $\begin{array}{|c|c|c|c|} \hline & \text { List-I } & & \text { List-II } \\ \hline & \text { EM-Wave } & & \text { Wavelength Range } \\ \hline \text { (A) } & \text { Infra-red } & \text { (I) } & < 10^{-3} \mathrm{~nm} \\ \hline \text { (B) } & \text { Ultraviolet } & \text { (II) } & 400 \mathrm{~nm} \text { to } 1 \mathrm{~nm} \\ \hline \text { (C) } & \text { X-rays } S & \text { (III) } & 1 \mathrm{~mm} \text { to } 700 \mathrm{~nm} \\ \hline \text { (D) } & \text { Gamma rays } & \text { (IV) } & 1 \mathrm{~nm} \text { to } 10^{-3} \mathrm{~nm} \\ \hline \end{array}$

  • Correct answer
    A
    (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  • B
    (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  • C
    (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  • D
    (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

Solution

Infrared is the least energetic thus having biggest wavelength $(\lambda) \&$ gamma rays are most energetic thus having smallest wavelength $(\lambda)$.

Hence, the correct answer is option: 'A'.

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