Q5 / 90 · JEE Main 2022 (25 Jul Shift 1) · Chemistry

Match List - I with List - II

 

List-II

  List-II
A N2g+3H2g→2NH3g I Cu
B COg+3H2g→CH4g+H2Og II Cu/ZnO-Cr2O3
C COg+H2g→HCHOg III FexOy+K2O+Al2O3
D COg+2H2g→CH3OHg IV Ni

Choose the correct answer from the options given below

  • A
    A-II,B-IV,C-I,D-III
  • B
    A-II,B-I,C-IV,D-III
  • Correct answer
    C
    A-III,B-IV,C-I,D-II
  • D
    A-III,B-I,C-IV,D-II

Solution

 

List-II

  List-II
A N2g+3H2g→2NH3g III FexOy+K2O+Al2O3
B COg+3H2g→CH4g+H2Og IV Ni
C COg+H2g→HCHOg I Cu
D COg+2H2g→CH3OHg II Cu/ZnO-Cr2O3

N2g+3H2g→2NH3g is Haber process and catalyst used are FexOy+K2O+Al2O3.

H2O + C → H2 + CO

The product of this is called synthesis gas and can be extremely useful in bonding with metallic heterogeneous catalysts to produce different organic compounds.

Hence, the correct answer is option: 'C'.

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