Q11 / 90 · JEE Main 2021 (01 Sep Shift 2) · Chemistry

Match List - I with List - II.

List-I
(Colloid Preparation Method)
List-II
(Chemical Reaction)
(a) Hydrolysis (i) 2AuCl3+3HCHO+3H2O→2Au(sol)+3HCOOH+6HCl
(b) Reduction (ii) As2O3+3H2 S→As2 S3(sol)+3H2O
(c) Oxidation (iii) SO2+2H2 S→3 S(sol)+2H2O
(d) Double Decomposition (iv) FeCl3+3H2O→Fe(OH)3(sol)+3HCl

Choose the most appropriate answer from the options given below :

  • A
    (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
  • Correct answer
    B
    (a)-(iv), (b)-(i), (c)-(iii), (d)-(ii)
  • C
    (a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)
  • D
    (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)

Solution

Colloid preparation by Hydrolysis reaction: (no change in oxidation number.)

FeCl3+3H2O→Fe(OH)3(sol)+3HCl

Gold sol is prepared by reduction reaction:

2AuCl3+3HCHO+3H2O→2Au(sol)+3HCOOH+6HCl

Preparation of sulphur sol:(oxidation)

SO2+2H2 S→3 S(sol)+2H2O

Preparation of colloid by double decomposition reaction:

As2O3+3H2 S→As2 S3(sol)+3H2O

Hence, the correct answer is option: 'B'.

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