Q14 / 170 · Manipal (MET) 2020 · Chemistry

Match List I (species) with List II (hybridisation) and select the correct code given below Figure
Codes $\begin{array}{llll}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D}\end{array}$

  • Correct answer
    A
    $\begin{array}{llll}(iii) & (ii) & (iv) & (i)\end{array}$
  • B
    $\begin{array}{llll}(i) & (iv) & (ii) & (iii)\end{array}$
  • C
    $\begin{array}{llll}(iii) & (iv) & (ii) & (i)\end{array}$
  • D
    $\begin{array}{llll}(i) & (ii) & (iv) & (iii)\end{array}$

Hence, the correct answer is option: 'A'.

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