Q14 / 170 · Manipal (MET) 2020 · Chemistry
Match List I (species) with List II (hybridisation) and select the correct code given below

Codes
$\begin{array}{llll}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D}\end{array}$

Codes $\begin{array}{llll}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D}\end{array}$
- Correct answerA$\begin{array}{llll}(iii) & (ii) & (iv) & (i)\end{array}$
- B$\begin{array}{llll}(i) & (iv) & (ii) & (iii)\end{array}$
- C$\begin{array}{llll}(iii) & (iv) & (ii) & (i)\end{array}$
- D$\begin{array}{llll}(i) & (ii) & (iv) & (iii)\end{array}$
Hence, the correct answer is option: 'A'.