Match List-I and List-II :

	List-I		List-II
a	Haematite	i	${\mathrm{Al}}_2{\mathrm{O}}_3·{\mathrm{xH}}_2\mathrm{O}$
b	Bauxite	ii	${\mathrm{Fe}}_2{\mathrm{O}}_3$
c	Magnetite	iii	${\mathrm{CuCO}}_3·\mathrm{Cu}(\mathrm{OH}{)}_2$
d	Malachite	iv	${\mathrm{Fe}}_3{\mathrm{O}}_4$

Choose the correct answer from the options given below :

• A

  $(\mathrm{a})-(\mathrm{ii}), (\mathrm{b})-(\mathrm{iii}),(\mathrm{c})-(\mathrm{i}),(\mathrm{d})-(\mathrm{iv})$
• B

  $(\mathrm{a})-(\mathrm{iv}) ,(\mathrm{b})-(\mathrm{i}),(\mathrm{c})-(\mathrm{ii}),(\mathrm{d})-(\mathrm{iii})$
• C

  $(\mathrm{a})-(\mathrm{i}),\; (\mathrm{b})-(\mathrm{iii}),\; (\mathrm{c})-(\mathrm{ii}),\; (\mathrm{d})-(\mathrm{iv})$
• Correct answer
  D

  $\left(\mathrm{a}\right)-\left(\mathrm{ii}\right), \left(\mathrm{b}\right)-\left(\mathrm{i}\right), \left(\mathrm{c}\right)-\left(\mathrm{iv}\right), \left(\mathrm{d}\right)-\left(\mathrm{iii}\right)$

Hence, the correct answer is option: 'D'.